]> www.pilppa.org Git - linux-2.6-omap-h63xx.git/commitdiff
CRISv10 memset library add lineendings to asm
authorJesper Nilsson <jesper.nilsson@axis.com>
Thu, 15 Nov 2007 01:01:32 +0000 (17:01 -0800)
committerLinus Torvalds <torvalds@woody.linux-foundation.org>
Thu, 15 Nov 2007 02:45:47 +0000 (18:45 -0800)
Add \n\ at end of lines inside asm statement to avoid warning.

No change except adding \n\ to end of line and correcting
whitespace has been done.
Removes warning about multi-line string literals when compiling
arch/cris/arch-v10/lib/memset.c

Signed-off-by: Jesper Nilsson <jesper.nilsson@axis.com>
Cc: Mikael Starvik <mikael.starvik@axis.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
arch/cris/arch-v10/lib/memset.c

index 82bb668391715279afb0619a46d3d4b208323ed5..42c1101043a3229481acf644ad947d0f427083dc 100644 (file)
@@ -66,7 +66,7 @@ void *memset(void *pdst,
 
   {
     register char *dst __asm__ ("r13") = pdst;
+
   /* This is NONPORTABLE, but since this whole routine is     */
   /* grossly nonportable that doesn't matter.                 */
 
@@ -110,52 +110,52 @@ void *memset(void *pdst,
       If you want to check that the allocation was right; then
       check the equalities in the first comment.  It should say
       "r13=r13, r12=r12, r11=r11" */
-    __asm__ volatile ("
-        ;; Check that the following is true (same register names on
-        ;; both sides of equal sign, as in r8=r8):
-        ;; %0=r13, %1=r12, %4=r11
-        ;;
-       ;; Save the registers we'll clobber in the movem process
-       ;; on the stack.  Don't mention them to gcc, it will only be
-       ;; upset.
-       subq    11*4,$sp
-        movem   $r10,[$sp]
-
-        move.d  $r11,$r0
-        move.d  $r11,$r1
-        move.d  $r11,$r2
-        move.d  $r11,$r3
-        move.d  $r11,$r4
-        move.d  $r11,$r5
-        move.d  $r11,$r6
-        move.d  $r11,$r7
-        move.d  $r11,$r8
-        move.d  $r11,$r9
-        move.d  $r11,$r10
-
-        ;; Now we've got this:
-       ;; r13 - dst
-       ;; r12 - n
-       
-        ;; Update n for the first loop
-        subq    12*4,$r12
-0:
-        subq   12*4,$r12
-        bge     0b
-       movem   $r11,[$r13+]
-
-        addq   12*4,$r12  ;; compensate for last loop underflowing n
-
-       ;; Restore registers from stack
-        movem [$sp+],$r10" 
+    __asm__ volatile ("\n\
+       ;; Check that the following is true (same register names on     \n\
+       ;; both sides of equal sign, as in r8=r8):                      \n\
+       ;; %0=r13, %1=r12, %4=r11                                       \n\
+       ;;                                                              \n\
+       ;; Save the registers we'll clobber in the movem process        \n\
+       ;; on the stack.  Don't mention them to gcc, it will only be    \n\
+       ;; upset.                                                       \n\
+       subq    11*4,$sp                                                \n\
+       movem   $r10,[$sp]                                              \n\
+                                                                       \n\
+       move.d  $r11,$r0                                                \n\
+       move.d  $r11,$r1                                                \n\
+       move.d  $r11,$r2                                                \n\
+       move.d  $r11,$r3                                                \n\
+       move.d  $r11,$r4                                                \n\
+       move.d  $r11,$r5                                                \n\
+       move.d  $r11,$r6                                                \n\
+       move.d  $r11,$r7                                                \n\
+       move.d  $r11,$r8                                                \n\
+       move.d  $r11,$r9                                                \n\
+       move.d  $r11,$r10                                               \n\
+                                                                       \n\
+       ;; Now we've got this:                                          \n\
+       ;; r13 - dst                                                    \n\
+       ;; r12 - n                                                      \n\
+                                                                       \n\
+       ;; Update n for the first loop                                  \n\
+       subq    12*4,$r12                                               \n\
+0:                                                                     \n\
+       subq    12*4,$r12                                               \n\
+       bge     0b                                                      \n\
+       movem   $r11,[$r13+]                                            \n\
+                                                                       \n\
+       addq    12*4,$r12 ;; compensate for last loop underflowing n    \n\
+                                                                       \n\
+       ;; Restore registers from stack                                 \n\
+       movem   [$sp+],$r10"
 
      /* Outputs */ : "=r" (dst), "=r" (n)
      /* Inputs */ : "0" (dst), "1" (n), "r" (lc));
-    
+
   }
 
     /* Either we directly starts copying, using dword copying
-       in a loop, or we copy as much as possible with 'movem' 
+       in a loop, or we copy as much as possible with 'movem'
        and then the last block (<44 bytes) is copied here.
        This will work since 'movem' will have updated src,dst,n. */